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Grade 12General Physics

If n=1 is taken to be the reference of the potential energy, what will be the kinetic energy (in eV) of an electron in second excited state in Li²+?

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Profile image of Ankush
8 Years agoGrade 12
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Profile image of SAKSHI
ApprovedApproved Tutor Answer8 Years ago
As its in question that second exited state so N=3  amd from formula total energy = -13.6*Z Square by N square      answer is -13.6    and now we have formula 
total energy = -K.E
-13.6 = -K.E 
SO, K.E is 13.6 eV             OPTION 1 OR A