If I have a torque of 2.5 million pounds feet moving at .71 FPS, how many KW are created?

To determine how many kilowatts (KW) are generated from a torque of 2.5 million pounds-feet moving at 0.71 feet per second (FPS), we can use the relationship between torque, angular velocity, and power. The formula to calculate power in terms of torque and angular velocity is:

Power Calculation Formula

The power (in watts) can be calculated using the formula:

Power (W) = Torque (lb-ft) × Angular Velocity (rad/s)

Converting Units

First, we need to convert the torque from pounds-feet to a more manageable unit and the velocity from feet per second to radians per second. Here’s how we can do that:

• Torque: 2.5 million pounds-feet is already in the correct unit.
• Angular Velocity: To convert linear velocity (FPS) to angular velocity (rad/s), we use the formula:

Angular Velocity (rad/s) = Linear Velocity (FPS) / Radius (ft)

However, we need the radius to proceed. If we assume a radius (r), we can express the angular velocity as:

Angular Velocity = 0.71 / r

Calculating Power

Now, substituting the angular velocity back into the power formula gives us:

Power (W) = Torque × (0.71 / r)

Substituting the torque value:

Power (W) = 2,500,000 × (0.71 / r)

Converting Power to Kilowatts

To convert watts to kilowatts, we divide by 1,000:

Power (KW) = (2,500,000 × 0.71) / (1,000 × r)

Now, we can simplify this further:

Power (KW) = 1,775,000 / r

Final Considerations

The final power output in kilowatts depends on the radius of the system. If you provide a specific radius, we can calculate the exact power output. For example, if the radius is 10 feet:

Power (KW) = 1,775,000 / 10 = 177,500 KW

In summary, to find the kilowatts generated from your torque and speed, the radius of the system is essential. Once you have that, you can easily plug it into the formula to get your answer!