badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

if E=ml^2t^-2 and frequency= t^-1 and planks constant = ml^2t^-1 are taken as fundamental units then find length and mass

2 years ago

Answers : (1)

Raksh
24 Points
							
calculating L.....
      [L]=[E]^a[frequecy]^b[plancks cont]^c
      [L]=[ML^2T^-2]^a [T^-1]^b[ML^2T^-1]^c
      [L]=[M]^a+0b+c[L]^2a+2c[T]^-2a-b-2c
   eqating dimensional powers.........
    [M]^0=[m]^a+0b+c
      0=a+b
      a=-b............(1)
     [L]=[L]^2a+2c
      1=2a+2c...........(2)
    [T]=[T]^-2a-b-2c
     1=-2a-b-2c
      as a=-b
      1=-2a+a-2c
       1=3a-2c........(3)
   from (2)and(3)
    2=5a
    a=2/5,b=-2/5,c=3/5.....unit of lenght=[E]^2/5[freq.]^-2/5[h]^3/5
similarly, mass can be derived
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details