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Grade 12General Physics

If a particle is moving along the curve y=sinx then the magnitude of the Point corresponding to X=π/2 is

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Profile image of Narendra
6 Years agoGrade 12
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1 Answer

Profile image of Brock
6 Years ago
y=sin x,
Differentiate wrt time, dy/dt = cosx dx/dt
Vy=cosx.Vx , at x=pi/2, Vy=0  => Vx=u
Again differentiate wrt time
Ay=cosx.Ax - Vx^2. Sinx,  at x=pi/2 
Ay=-u^2 and Ax=0(since at that instant body is moving with constant speed in x direction)
Therefore, net acc. magnitude= u^2.