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Grade: 11
        If a body loses half its velocity on penetrating 3cm in a wooden block, them how much will it penetrate more before coming to rest?
3 years ago

Answers : (2)

Vikas TU
11138 Points
							
With penetrating 3 cm block,
v^2/4 = v^2 – 2a*3
3v^2/4 = 6a
v^2 = 8a.........(1)
Now,
0^2 = v^2 – 2ax.......(2)
put (1) in (2)
x = 1 cm
net distance would be => 1 + 3 = 4cm.
3 years ago
Samuel Garry
61 Points
							
First case
initial velocity(u)=v , final velocity(v)=v/2 ;distance covered(s)=3cm
we know 2as=v2-u2  
2*a*3=(v/2)2 - v2
a= -v2 / 8
in second case
initial velocity(u)=v , final velocity(v)=o ;distance covered(s)=we hav to find out
here we know acceleration=-v2 / 8
2as=v2-u2  
2*(v2 / 8)*s=(0)2 - v2
on solving we get
s=4cm
but it had already pnetrated 3 cm thrfore it will pertrate 1 cm more to come to rest
2 years ago
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