Grade 10General Physics
If a ball is projected vertically upward then the distance travelled by the ball in last second ?
3 Answers
deekshit
let us consider a ball moves height h in t-1 seconds
then h=u(t-1)-1/2g(t-1)^2.
if max height reached is H in t seconds.
then H=ut-1/2gt^2.
subracting both u’ll get H-h=u+g/2(1-2t).
deekshit
substituting t=1 we will get correct answer i.e.u-g/2.
this gives correct answer.substituting t=1 is misssed in my answer.i want to known why my answer is treated as disapproved as i gave clear explanation
deekshit
ANOTHER METHOD DSTANCE TRAELLED IN NTH SECOND IS( S=U+a(n-1/2))
from this also we can get u-g/2. as u=u,a=-g,n=1.here we take n=1 because
distance travelled in first second of upward journey = distance travelled in last second of journey.
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