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if |A×B|=root3(A.B)vector then find the value of (A+B)vector
AxB= absin (theta)A.B= abcos (theta)From given conditon it followssin (theta)= root3cos (theta)which means theta is 60.For getting A+B we need magnitudes of these vectors as well. We have got angle from above relation.
A×B is a Vector and A.B is a scalar. They can never be equal to each other.However their magnitudes can be of same value.→ Case(i) Assume that the actual question is :- ( If |A×B|=|√3A.B| , then what is the value of |A+B| ? )(1) First possibility → Let A and B are non-zero vectors,Then,|A×B|= |ABsin $|where, $ is the angle between A and B vectors.A.B= ABcos $Where, $ is the angle between A and B vectors.A/QABsin $= √(3)ABcos $=> tan$= √(3)=> $ = 60°
A×B is a Vector and A.B is a scalar. They can never be equal to each other.
However their magnitudes can be of same value.
→ Case(i) Assume that the actual question is :- ( If |A×B|=|√3A.B| , then what is the value of |A+B| ? )
(1) First possibility → Let A and B are non-zero vectors,
Then,
|A×B|= |ABsin $|
where, $ is the angle between A and B vectors.
A.B= ABcos $
Where, $ is the angle between A and B vectors.
A/Q
ABsin $= √(3)ABcos $
=> tan$= √(3)
=> $ = 60°
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