Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        iam attached a image please give me solution.and explain how we take angle in that case ?`
3 years ago

ESWAR REDDY
11 Points
```							givenw=100NFROM Equilibrium conditionFORCE ALONG Y-DIRECTION IS ‘0’T2-w=0T2=w=100N------(1)AT POINT PWE RESOLVE THE T1 INTO COMPONENTSALONG negative X-direction we take T1Sin anglealong positive y-direction we take T1Cos angleFy=0(Equilibrium condition)T1Cos angle-T2=0T1Cos angle=T2FROM (1)T1Cos angle=100N-----(2)Fx=0(Equilibrium condition)100-T1Sin angle=0100=T1Sin angle------(3)(3)/(2),we gettan angle=1angle =1/tan(tan 45)angle=45
```
3 years ago
54 Points
```							givenW=100Nfrom equilibrium,T2-w=0t2=100N..........(1)at point p the components are,Fy=0T2-COT1S angle=0T2=T1cos anglefrom (1)T1cos angle=100.................(2)Fx=0100-T1sin angle=0T1 sin angle=100..................(3)from(3)/(2)we getT1 sin angle               T2--------------------    =   -----------T1 cos angle              T2 TAN angle=1therefore  angle=1/tan(45)angle=45
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions