×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
i can’t solve this question. i think this is the tougest proble so please help to solve this question.
i can’t solve this question. i think this is the tougest proble so please help to solve this question.

```
2 years ago

Arun
25768 Points
```							First, we write all the known quantities a= -10m's^2s= 390 mu= +10m/ss=ut + 1/2at^2s=10t + 5t^2-390=10t + 5t^2-78= 2t - t^2t^2 - 2t - 78 = 0d= b^2 - 4acd= 4 + 312d= 316-b±√d/2a2±2√79/2=1±79.therefore time taken to hit the ground will be 1+√79
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions