How would I determinethe maximum number of letres of milk (with a density of 1030Kg m^-3 ) that can be added to a 50L drum that weights 70N when empty, so that the drum will float in fresh water (density 1000 Kg m^-3)

Question

bharat bajaj · Answer

If the drum would float in water, then its density should be less than that of water
p < 1000

Say x litres of milk can be added.
Mass of drum = 70/10+ 1.03x ( Here x is in litres. Convert units)
Volume of drum = 50
p = M/V = (7 + 1.03x)/(50/1000) < 1000
7 + 1.03x < 50
x < 43/1.03
This is the maximum milk which you can add.
Thanks

Bharat Bajaj
IIT Delhi

askiitians faculty

KAPIL MANDAL · Answer

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How would I determinethe maximum number of letres of milk (with a density of 1030Kg m^-3 ) that can be added to a 50L drum that weights 70N when empty, so that the drum will float in fresh water (density 1000 Kg m^-3)

How would I determinethe maximum number of letres of milk (with a density of 1030Kg m^-3 ) that can be added to a 50L drum that weights 70N when empty, so that the drum will float in fresh water (density 1000 Kg m^-3)

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How would I determinethe maximum number of letres of milk (with a density of 1030Kg m^-3 ) that can be added to a 50L drum that weights 70N when empty, so that the drum will float in fresh water (density 1000 Kg m^-3)

How would I determinethe maximum number of letres of milk (with a density of 1030Kg m^-3 ) that can be added to a 50L drum that weights 70N when empty, so that the drum will float in fresh water (density 1000 Kg m^-3)

2 Answers

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