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How to integrate dv/DT=a-bv please tell fast my test is today
a= dv/dt,v=dr/dt.hence, ∫dv=∫adt-b∫vdt=v-br+c=vor, c=br. assuming of course a= acceleration,v=velocity,r= postion of particle
dv/dT = a-bvdv/(a- bv) = dTNow integrate it- [ln(a- bv)]/b = T + constant NOTE- you can also take constant in the form of lnHope it helps
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