Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        How to find percentage decrease in the weight of the body when take to height 32 km above the surface of earthif radius of earth is 6400 km...Ans is 1 % how?`
3 years ago

Vishal
19 Points
```							g(h)= g(1-2h/r) { g(h)- gravity at height h % decrease= 1 Kitna likhu bhai? Samjh ja ab I am anonymous trying to help but these people are not allowing me to do so.
```
3 years ago
Sonia Paruthi
14 Points
```							Here d= 32 km R= 6400 kmweight of body at depth d is mg` =mg(1-d/R)% decrease in weight =( mg- mg`)/mg × 100= 32 / 6400×100 = 0.5%.
```
2 years ago
Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

View all Questions »

Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions