Grade 9General Physics

Hello .. Can you explain with steps ??

Two particles of masses 4kg and 6kg are at rest separated by 20m. If they move towards each other under mutual force of attraction, the position of the point where they meet is

jeeva

9 Years agoGrade 9

1 Answer

Piyush Kumar Behera

9 Years ago

Please try to understand what i am writing in the solution.

You must be knowing that the centre of mass of a system of particle moves and accelerates only under the influence of external force..

as the bodies move under the mutual attractive forces(i.e. internal forces) and hence there is no net external force.

so the centre of mass remains at rest.

now when they collide there centre of mass must be at the same position,and to make it possible the only choice is that they will collide at the centre of mass.

calculate the centre of mass position initially and that will be the place where they collide

please upvote the solution so that i get encouraged and i can answer rest of your questions

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Hello .. Can you explain with steps ?? Two particles of masses 4kg and 6kg are at rest separated by 20m. If they move towards each other under mutual force of attraction, the position of the point where they meet is

jeeva

1 Answer

Piyush Kumar Behera

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Hello .. Can you explain with steps ??

Two particles of masses 4kg and 6kg are at rest separated by 20m. If they move towards each other under mutual force of attraction, the position of the point where they meet is

. Because of the rotation of the earth, a plumb bob may not hang exactly along the direction of
the earth’s gravitational pull (its weight) but deviates slightly from this direction. Calculate the
deviation (a) at 40 latitude, (b) at the poles, and (c) at the equator