Grade 9General Physics

Hello …..
A ball falls freely from rest on a perfectly elastic surface from a height of 3 m . Draw the v- t graph for it upto 5 seconds.

jeeva

9 Years agoGrade 9

1 Answer

Saurabh Koranglekar

6 Years ago

The balls falls on a perfectly elastic platform, hence it will rebounce back without undergoing any loss of energy.

Hence, using second law of motion
s = ut + 1/2gt^2
u = 0, s = 3, g = 10
Hence, t = sqrt(60) = 2sqrt(15) sec

Also,the velocity with which it will hit the platform would be
v = u + at
v = 10*2sqrt(15)
v =20sqrt(15)

Hence, the ball will fall on the platform at t = 2sqrt(15) sec with a velocity of 20sqrt(15) m/s.
Since, the acceleration (retardation) is constant, hence velocity-time graph will initially be a straight line of positive slope from (0,0) to (2sqrt(15),20sqrt(15)) and then it will straight line with negative slope from(2sqrt(15),20sqrt(15)) to(4sqrt(15),0). This pattern of the graph will keep on repeating as there is no loss of energy.

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Hello ….. A ball falls freely from rest on a perfectly elastic surface from a height of 3 m . Draw the v- t graph for it upto 5 seconds.

jeeva

1 Answer

Saurabh Koranglekar

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Hello …..
A ball falls freely from rest on a perfectly elastic surface from a height of 3 m . Draw the v- t graph for it upto 5 seconds.

. Because of the rotation of the earth, a plumb bob may not hang exactly along the direction of
the earth’s gravitational pull (its weight) but deviates slightly from this direction. Calculate the
deviation (a) at 40 latitude, (b) at the poles, and (c) at the equator