Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Given the mass of iron nucleus as 55.85u and A=56, find the nuclear density?

Given the mass of iron nucleus as 55.85u and A=56, find the nuclear density?

Grade:11

1 Answers

suraj sarma
13 Points
3 years ago
According to rutherford`s relationsradius of nucleus = ro×A13 ro = constant = 1.2×10−15 mthereforer = 1.2×10−15 ×56−−√3r = 4.59 ×10−15 malso,1u = 1.67×10−27 kg55.85 u = 9.327 ×10−26 kg = mass of nucleus of iron atomnuclear density = mass of nucleus of iron atomvolume of nucleus nuclear density = 9.327 ×10−26 kg43π×r3 =9.327 ×10−26 kg43π×(4.59 ×10−15 )3nuclear density = 4.851×1018 kg/m^3

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free