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Grade 10General Physics

from a point A,80m above the ground , the particle is projected vertically upwards with a velocity of 29.4ms-1. 5 seconds later, another particle is dropped from a point B,34.3m vertically below A . when and where one overtakes the other [take g=9.8ms-2]

Profile image of sahana
7 Years agoGrade 10
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1 Answer

Profile image of Darshil Patel
7 Years ago
Please apply this equation
h+34.3=29.4+(-1/2)gt^2
So t=8 sec
H=45.7m......
h=1.6m......
Okay understand