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from a point A,80m above the ground , the particle is projected vertically upwards with a velocity of 29.4ms-1. 5 seconds later, another particle is dropped from a point B,34.3m vertically below A . when and where one overtakes the other [take g=9.8ms-2]

sahana , 7 Years ago
Grade 10
anser 1 Answers
Darshil Patel
Please apply this equation
h+34.3=29.4+(-1/2)gt^2
So t=8 sec
H=45.7m......
h=1.6m......
Okay understand
 
Last Activity: 6 Years ago
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