Four particles are at corners of a square. All particles are moving in a circle of radius ‘R’ with constant speed v. Find the value of v.Answer is v = root(Gm/2R [1/2 + root 2])
Kaushal Negi , 5 Years ago
Grade 11
1 Answers
Vikas TU
Last Activity: 5 Years ago
Dear student
The question is little bit confusing , It is on square and moving on circle ,
Please post the image . We will help you ,
Good Luck
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