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Four particles are at corners of a square. All particles are moving in a circle of radius ‘R’ with constant speed v. Find the value of v. Answer is v = root(Gm/2R [1/2 + root 2])

Four particles are at corners of a square. All particles are moving in a circle of radius ‘R’ with constant speed v. Find the value of v.
Answer is v = root(Gm/2R [1/2 + root 2])

Grade:11

1 Answers

Vikas TU
14149 Points
4 years ago
Dear student 
The question is little bit confusing , It is on square and moving on circle , 
Please post the image . We will help you , 
Good Luck 
 

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