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Four particles are at corners of a square. All particles are moving in a circle of radius ‘R’ with constant speed v. Find the value of v.Answer is v = root(Gm/2R [1/2 + root 2])

Kaushal Negi , 5 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 5 Years ago

Dear student 
The question is little bit confusing , It is on square and moving on circle , 
Please post the image . We will help you , 
Good Luck 
 

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