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`        Four identical masses (each equal to m) are placed at corners of a square of side ‘a’ then calculate the force experienced on one of the mass due to other massesAnswer is |Fnet| = Gm2/a2 [1/2 + root2]`
3 months ago

Arun
23520 Points
```							F (Net) = (4 x G x M x M1) / (r^2)Since the given masses are ideal point masses and do not exhibit any electrical characters, we are free to use Newton’s Law of Gravity.The force of attraction between the 4 bodies placed at the boundary and the lone mass placed at the centre can be given by the application of the following formula 4 times:F = (G x M x M1) / (r^2)Where, G is universal gravitational constant and r is the distance between the central mass and boundary mass.Since each mass exerts the above force, the combined force felt by the central mass will be:F(Net) = (4 x G x M x M1) / (r^2)
```
3 months ago
Vikas TU
10070 Points
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3 months ago
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• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions