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Grade: 11
Four identical masses (each equal to m) are placed at corners of a square of side ‘a’ then calculate the force experienced on one of the mass due to other masses
Answer is |Fnet| = Gm2/a2 [1/2 + root2]
7 months ago

Answers : (2)

24735 Points
F (Net) = (4 x G x M x M1) / (r^2)
Since the given masses are ideal point masses and do not exhibit any electrical characters, we are free to use Newton’s Law of Gravity.
The force of attraction between the 4 bodies placed at the boundary and the lone mass placed at the centre can be given by the application of the following formula 4 times:
F = (G x M x M1) / (r^2)
Where, G is universal gravitational constant and r is the distance between the central mass and boundary mass.
Since each mass exerts the above force, the combined force felt by the central mass will be:
F(Net) = (4 x G x M x M1) / (r^2)
7 months ago
Vikas TU
11678 Points
Dear student 
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Good Luck 
7 months ago
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