MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
Four identical masses (each equal to m) are placed at corners of a square of side ‘a’ then calculate the force experienced on one of the mass due to other masses
Answer is |Fnet| = Gm2/a2 [1/2 + root2]
7 months ago

Answers : (2)

Arun
24735 Points
							
F (Net) = (4 x G x M x M1) / (r^2)
Since the given masses are ideal point masses and do not exhibit any electrical characters, we are free to use Newton’s Law of Gravity.
The force of attraction between the 4 bodies placed at the boundary and the lone mass placed at the centre can be given by the application of the following formula 4 times:
F = (G x M x M1) / (r^2)
Where, G is universal gravitational constant and r is the distance between the central mass and boundary mass.
Since each mass exerts the above force, the combined force felt by the central mass will be:
F(Net) = (4 x G x M x M1) / (r^2)
7 months ago
Vikas TU
11678 Points
							
Dear student 
Please attach an image of the question , 
We will happy to help you ….............
Good Luck 
7 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details