Given Vector magnitude of vector A=130 N
magnitude of vector B=200 N
also stated that A is along vector OA (where O is orign & A(3,-4,12))
& B is along the vector PQ where P(-2,4,7) Q(-2,8,10)
First we find the Unit vectors for both OA and PQ
Unit veector of OA=vector OA divided by Magnitude of OA
=3i-4j+12k / Sq.Root of 32+(-4)2+122
=3/13 i – 4/13 j +12/13 k
Now Unit vector of PQ=vector PQ divided by Magnitude of PQ
={ -2-(-2)i+8-(4)j +10-(7)k} / Sq.Root of 02+42+32
=0i+4j+3k / 5
=4/5 j +3/5 k
Therefore Vector A={3/13 i -4/13 j +12/13 k}×130
=30i-40j+120k
Vector B={4/5 i+ 3/5 k}×200
=160i +120k
Vector Sum of A and B={ (0-30)i+(160+40)j+(120-120)k}
=-30i+200j
Hence Solved.
