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Find the pressure on a swimmer 10 metre below the surface of a lake. take density of a lake water=10³ kg /metre³ and atmospheric pressure is equal to 1.01×10⁴×10Pascal

yogesh Chaudhary , 8 Years ago
Grade 11
anser 1 Answers
Khimraj

Last Activity: 8 Years ago

Pressure at depth d is given byP = Patm + ρgdSo pressure on swimmer = 1.01×10⁴×10Pascal + 1000*9.8*10 = 199000 pascal = 1.99 kilopascal
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