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Grade: 12th pass
        
Find pressure at point A in the given figure.........
one month ago

Answers : (2)

Samyak Jain
325 Points
							Let the adjacent point of sides l2 and l3 be B and that of sides l1 and l2 be D and the free surface of liquid at open end of pipe be E.Pressure at E = atmospheric pressure = Patm.Since fluid is static, pressure difference is due to height of fluid.Pressure at C = Pressure at E + \rhogh1,\rho = density of fluid in pipe and h1 = height of fluid between E and C = l1 sin\theta1.i.e. PC = Patm + \rhogl1 sin\theta1.Pressure at C = Pressure at B + \rhogh2 ,  h2 = l2 sin\theta2.i.e. PC = PB + \rhogl2 sin\theta2   \Rightarrow  PB = PC – \rhogl2 sin\theta2 = Patm + \rhogl1 sin\theta1 – \rhogl2 sin\theta2Similarly, PA = PB + \rhogl3 sin\theta3 = Patm + \rhogl1 sin\theta1 – \rhogl2 sin\theta2 + \rhogl3 sin\theta3PA = \rhog(l1 sin\theta1 – l2 sin\theta2 + l3 sin\theta3) = pressure at A .
						
14 days ago
Samyak Jain
325 Points
							
Let the adjacent point of sides l2 and l3 be B and that of sides l1 and l2 be C and the free surface of fluid
at open end of pipe be D.
 
Pressure at D = atmospheric pressure = Patm.
Since fluid is static, pessure difference is due to height of fluid.
 
Pressure at C = Pressure at D + \rhogh1 .
\rho = density of fluid in pipe and h1 = height of fluid between E and C = l1 sin\theta1 .
PC = Patm + \rhogl1 sin\theta1 .
 
Pressure at C = Pressure at B + \rhogh2 ,  h2 = l2 sin\theta2 .
PC = PB + \rhogl2 sin\theta2   \Rightarrow   PB = PC\rhogl2 sin\theta2  =  Patm + \rhogl1 sin\theta1\rhogl2 sin\theta2 
 
Similarly, PA = PB + \rhogl2 sin\theta3  =  Patm + \rhogl1 sin\theta1\rhogl2 sin\theta2 + \rhogl3 sin\theta3 
PA = Patm + \rhog(l1 sin\theta1 – l2 sin\theta2 + l3 sin\theta3) = pressure at A .
14 days ago
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