F=20N,m1=m2=3and acceleration is 0.5m/s^2.Friction forces on the two blocks are eaqual what is magnitude
Sajidh salih , 5 Years ago
Grade 10
Mechanics> F=20N,m1=m2=3and acceleration is 0.5m/s^2...
1 Answers
Arun
Last Activity: 5 Years ago
First consider the 2 masses as a single object. Total mass = 3+3=6 kg
Resultant force, F= ma = 6 x 0.5 = 3N
Since an external force of 20N is being applied, the frictional force must be 20-3=17N
(8.5N on each mass).
Now consider m1 by itself. The resultant force on it = ma = 3 x 0.5=1.5N
Let T = tension in rope joining m1 and m2
Let T = tension in rope joining m1 and m2
The only 2 horizontal forces on m1 are T (to right) and 8.5N (friction to the left)
Resultant horizontal force on m1 = T1 - 8.5
T-8.5 = 1.5
T = 10N
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