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∫dx/root2ax-x2=a^nsin^-1[x/a-1].find the value of n

∫dx/root2ax-x2=a^nsin^-1[x/a-1].find the value of n

Grade:11

2 Answers

Nicho priyatham
625 Points
8 years ago
0
 
PLZ APPROVE IF CORRECT
Nicho priyatham
625 Points
8 years ago
well dats not sin^-1 its sin -1 or arcsin or sin invers

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