During heavy rain, a section of a mountainside me

Question

During heavy rain, a section of a mountainside measuring 2.5km horizontally, 0.80km up along the slope, and 2.0 m deep slips into a valley in a mud slide. Assume that the mud ends up uniformly distributed over a surface area of the valley measuring 0.40 km 0.40km and that mud has a density of 1900 kg/m3. What is the mass of the mud sitting above a 4.0m2 area of the valley floor? I can't seem to understand what the question is getting at...like, I tried to draw a picture, and I don't think it was correct.How can the volume be found without knowing the shape of the mountin?

Vikas TU · Accepted Answer

To start with we need to need to know the volume of mud that descends: As mountain side measuring 2.5km on a level plane, 0.80km up along the incline, and 2.0 m profound 2500 X 800 X 2 = 4000000m^3 of mud. Presently we have to know how profoundly this covers the floor of the valley: Region of the valley = 400 X 400 =160000m^2 So the profundity of the mud = 4000000/160000 = 25m. Along these lines, now that we realize that the mud is 25m profound, we can work out the volume of mud covering the region being referred to: 25 X 4 = 100m^3 So there is 100m^3 of mud. We can work out its mass utilizing rho = m/V, so m = rho X V = 1900 X 100 = 190000kg = 190 Mg.

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General Physics> During heavy rain, a section of a mountai...

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