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`        Determine the speed with which the Earth would have to rotate on its axis so that a person on the equator would weigh(3/5)th as much as present.take the equatorial radius as 6400 km.`
2 years ago

Arun
23342 Points
```							Dear Saurabh  True weight at the equator, W = mgObserved weight at the equator,W' = mg' = (3/5)mgat the equator λ = 0 mg' = mg - mRw² cosλ 3mg/5 = mg - mRw². Cos 0 = mg - mRw² mRW² = 2mg/5 w = 7.8 * 10^-4 rad/ sec RegardsArun(askIITians forum expert)
```
2 years ago
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