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Consider a tightly wound 100 turns of a coil of radius 1 cm carrying a current of 1A . What is the magnitude of the magnetic field at the center of the coil ?

Consider a tightly wound 100 turns of a coil of radius 1 cm carrying a current of 1A . What is the magnitude of the magnetic field at the center of the coil ?

Grade:12

1 Answers

Arun
25750 Points
5 years ago

Number of turns on the circular coil, n = 100

Radius of each turn, r = 1.0 cm = 0.01 m

Current flowing in the coil, I = 1p A

Magnitude of the magnetic field at the centre of the coil is given by the relation,

| B | = μ0 2πnI / 4π r

Where,

μ= Permeability of free space

= 4π × 10–7 T m A–1

| B | = 4π x 10-7 x 2π x 100 x 1 / 4π x 0.01

       = 62.8 x 10-4 T

Hence, the magnitude of the magnetic field is 62.8 × 10–4 T.

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