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Confusion in significant result! In case of significant result 3.1*10^5 - 1.2*10^4 = 30*10^4= 3.0*10^5. and 10+1=10. Please read the description In case of significant result 3.1*10^5 - 1.2*10^4 = 30*10^4= 3.0*10^5. That means there is 2 significant no and we can't avoid '0' from '30' because we got it by substruction. But, in case of significant result, when we add 10+1=10 then why we don't count 2 significant numbers and we also got it by the addition that directly means we are avoiding 0 here! But why we do it, unlike the previous operation?

Confusion in significant result! In case of significant result 3.1*10^5 - 1.2*10^4 = 30*10^4= 3.0*10^5. and 10+1=10. Please read the description
In case of significant result 3.1*10^5 - 1.2*10^4 = 30*10^4= 3.0*10^5. That means there is 2 significant no and we can't avoid '0' from '30' because we got it by substruction. But, in case of significant result, when we add 10+1=10 then why we don't count 2 significant numbers and we also got it by the addition that directly means we are avoiding 0 here! But why we do it, unlike the previous operation?

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Grade:12th pass

1 Answers

Muhammad Rashid
15 Points
3 years ago
A zero to the right of significant figures may or may not be zoro 
In decimal fraction zeros to the right of significant figures are significant 
A zero between two significant figures is itself significant 
Zeros to the left of significant figures are not significant 

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