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can you please solve integral of sinx +cosx limits from pi/2 to 0 answer is. +2
integration of sinx+cosx=integration of sinx + integration of cosxintegration of sinx =-cosxapplying limits feom 0 to pi/2 i.e,-cospi/2-(-cos0)=0+1=1.............Aintegration of cosx=sinx applying limits from pi/2 to 0 i.e.,sinpi/2-sin0=1............BAdding a and b i.e,1+1=2
Integral of sin x = - cos xInyegral of cos x = sin xHence integral of question will be = Sinx - cos xBut if apply the limitThen answer == Sin (pi/2) - cos(pi/2) -[sin 0 - Cos 0]= 1- 0 - 0 + 1=2
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