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8 months ago

Ayush_Deep
120 Points
```							For a rod the change in length dl = Feff L/AYFeff is the average force which is equal to average force across ends.Let's assume a force F is applied at one end and other end is rigid (F=0) average force is F+0/2=F/2In the above question ,Net force on rod is zeroF + mg = boyant force = 2DVg D density of rod V volume of rodm mass of rodF + DVg = 2DVg F= DVgBoyant force = 2DVg =2FTherefore force on one end is F and on lower end is 2FFeff is (F+2F)/2 =3F/2= 3DVg/2Extension in rod is 3FL/2AY = 3DVgL/2AY=3DL²g/2YHence option 2 is correctWhatsApp 9262659488Good regards
```
8 months ago
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