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Grade: 12


Can you please help me with the solution of question 8 only??

5 months ago

Answers : (1)

120 Points
For a rod the change in length dl = Feff L/AY
Feff is the average force which is equal to average force across ends.
Let's assume a force F is applied at one end and other end is rigid (F=0) average force is F+0/2=F/2
In the above question ,
Net force on rod is zero
F + mg = boyant force = 2DVg 
D density of rod 
V volume of rod
m mass of rod
F + DVg = 2DVg 
F= DVg
Boyant force = 2DVg =2F
Therefore force on one end is F and on lower end is 2F
Feff is (F+2F)/2 =3F/2= 3DVg/2
Extension in rod is 3FL/2AY = 3DVgL/2AY=3DL²g/2Y
Hence option 2 is correct
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Good regards
5 months ago
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