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Grade: 12
        calculate  the  shortest  distance  in which  an automobile  moving  with  a  speed of  108  km/h can be  stopped  .If the  coefficient  of  friction  between  the  tires  and  the  road  is 0.74  .Also  calculate  the  retardation  .
2 years ago

Answers : (1)

Eshan
askIITians Faculty
2095 Points
							The maximum frictional force acting on a body is\mu N=\mu mg
Hence the maximum retardation of the body=\dfrac{\mu mg}{m}=\mu g=7.4m/s^2

Initial speed of the body=108km/h=30m/s

Hence the shortest distance in which the automobile stops=\dfrac{u^2}{2a}=\dfrac{30\times 30}{2\times 7.4}m=60.8m
one year ago
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