MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        Calculate the ratio of the reaction of a convex bridge at the highest point of the reaction of the concave bridge at its lowest point when a car passes at 30 km/hr and the radius of either bridge is 20m
2 years ago

Answers : (1)

Arun
23544 Points
							
Dear Student
 
The forces acting on the car are weight mg  and normal reaction from the road on the bridge.  We ignore friction and Thrust force of engine for this calculation.  As the car is moving at uniform speed, friction and engine thrust are equal and opposite. They are perpendicular to radius and so  do not contribute to the centripetal force. 

        v = 30 kmph = 25/3 m/s

1) Convex: centripetal force :
           mg - N1 = m v² / R       =>  N1 = m (g - v^2/R) = m*235/36 N

2) Concave bridge:  
          N2 - mg = m v²/R      =>  N2 = m (g + v²/R) = m *485/36  N

Ratio:   N1/ N2 = 235/485 = 47/97
 
Regards
Arun (askIITians forum expert)
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details