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Calculate the (a) momentum, and (b) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.

Jayant Kumar , 10 Years ago
Grade 11
anser 1 Answers
Apoorva Arora

Last Activity: 10 Years ago

E= 56 eV
soP=\sqrt{2mKE}=4.04\times 10^{-24}
So,\lambda =\frac{h}{P}
\lambda =1.64 angstrom
Thanks and Regards
Apoorva Arora
IIT Roorkee
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