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AT WHAT ANGLE WITH THE HORIZONTAL SHOULD A BALL BE THRWN SO THAT THE RANGE R IS RELATED TO TIME OF FLIGHT ‘T’ AS R=5T^2
R=5T^2(u^2*sin2 theta)/g=5*[(2*u*sin theta)/g]^2(u^2*sin2 theta)/g=5*4*u^2*sin^ 2theta/g^2sin2 theta*g=5*4*sin^2theta10sin2 theta=20sin^2 theta (g=10)sin2 theta=2sin^2 theta2sin theta*cos theta=2sin^2 theta (sin2 theta=2sin theta*cos theta)sin theta*cos theta=sin^2 thetacos theta = sin thetacot theta = 1i.e. theta= 45 degree
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