×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

At given place acceln due to gravity is g m/s* a sphere of lead of density d is gently released in column of liquid of density €. If d> €The sphere will fall with acceleration
At given place acceln due to gravity is g m/s* a sphere of lead of density d is gently released in column of liquid of density €. If d> €The sphere will fall with acceleration


4 years ago

DR STRANGE
212 Points
							Hi Nizam,buoyant force (upward) = V*€*g     V=volume of sphereforce due to gravity (downward) =Mg= d*V*g …........... (   M=V*d )net force F=Ma=d*V*a = downward – upward=V*g*(d-€)hence $a=\frac{g(d-\euro )}{d}=g(1-\frac{\euro }{d})$Plz approve if you are satisfied :)

4 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions