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at an instant car A Is moving with constant velocity of 30 m/s and a stationary car B with acc. 2 m/s^2 in same direction and location, the time after which they cross each other
Let car A covered the distance as 'x’ meters then,x = 30*t.................(1) For car B,x = 0 + 0.5*2*t^2...............(2)solving both the eqns. we get,t^2 = 30tt (t – 30 ) = 0t = 30 seconds.
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