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appointment with uniform acceleration and V1 V2 and V3 denote the average Lost Season 3 of the interval of time T1 T2 and T3 which of the following relation is correct

Anuj , 8 Years ago
Grade 12th pass
anser 1 Answers
Sanju
Lets assume that the particles move distances AB, BC and CD during the time t1, t2 and t3 respectively..
Velocity at B = u+at
Vel. at C =  u+a(t+ t2)
Vel. at D =  u+a(t+ t2 + t3)
Avg velocity = [u+v] / 2
Therefore, v= [u + (u+at)] / 2 = u+½ at1
v= [(u+at) + (u+a(t+ t2))] / 2 = u+at1+½ at
v= [ (u+a(t+ t2) +  (u+a(t+ t2 + t3)] / 2 = u+at1+at2+½ at3  
Finally we arrive at:
v1-v2 / v2-v3 = t1+t2 / t2+t3
Ans: Option B
Last Activity: 8 Years ago
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