Flag General Physics> An object length 2.5cm is placed at a dis...
question mark

An object length 2.5cm is placed at a distance of 1.5f from a concave mirror where f is the focal length of the mirror. The length of object is perpendicular to principal axis. Find the size of image. Is the image is erect or inverted?

Manvendra Singh chahar , 12 Years ago
Grade Upto college level
anser 1 Answers
Askiitians Tutor Team

To determine the size of the image formed by a concave mirror when an object is placed at a distance of 1.5 times the focal length (1.5f), we can use the mirror formula and magnification concepts. Let’s break this down step by step.

Understanding the Mirror Formula

The mirror formula is given by:

1/f = 1/v + 1/u

Where:

  • f = focal length of the mirror
  • v = image distance from the mirror
  • u = object distance from the mirror (taken as negative in the case of concave mirrors)

Setting Up the Problem

In this scenario, the object length is 2.5 cm, and it is placed at a distance of 1.5f from the mirror. Since we are dealing with a concave mirror, we take the object distance (u) as:

u = -1.5f

Applying the Mirror Formula

Substituting the value of u into the mirror formula:

1/f = 1/v + 1/(-1.5f)

This simplifies to:

1/v = 1/f + 1/(1.5f)

Finding a common denominator (which is 1.5f), we get:

1/v = (1.5 + 1) / (1.5f) = 2.5 / (1.5f)

Thus, we can express v as:

v = (1.5f) / 2.5 = 0.6f

Calculating the Magnification

The magnification (m) of the image can be calculated using the formula:

m = -v/u

Substituting the values we found:

m = - (0.6f) / (-1.5f) = 0.4

This means the image is 0.4 times the size of the object.

Finding the Size of the Image

Now, to find the size of the image (h'), we use the magnification formula:

h' = m × h

Where h is the height of the object (2.5 cm):

h' = 0.4 × 2.5 cm = 1 cm

Determining the Orientation of the Image

Since the magnification is positive (0.4), this indicates that the image is erect. However, for concave mirrors, when the object is placed beyond the focal point, the image is typically inverted. In this case, because the object is at 1.5f, which is beyond the focal point, the image will actually be inverted despite the positive magnification value indicating size.

Final Summary

To summarize:

  • The size of the image is 1 cm.
  • The image is inverted.

Thus, when dealing with concave mirrors, always consider both the magnification and the position of the object relative to the focal point to determine the nature of the image accurately.

ApprovedApproved
Last Activity: 10 Months ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments