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an object is projected with speed 20m/s at an angle 60 with vertical. how much time it will take to cross 2 equalpoles of height 4m
an object is projected with speed 20m/s at an angle 60 with vertical. how much time it will take to cross 2 equalpoles of height 4m


2 years ago

Khimraj
3007 Points
							time will equal to 2 times of time taken from max height to height of 4m.max height = u2sin260/2g = 400*3/(4*20) = 15mthen H-4 = 15-4 = 11then t = 2*($\sqrt{11*2/10}$) = $2\sqrt{11/5}$sHope it clears.

2 years ago
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