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An electronic dipole of moment P is placed in a uniform electric field E. Derive the expression for the potential energy of the dipole and show diagrammatically the orientation of the dipole in the field for which the potential energy is (i) maximum (ii) minimum.?

Manvendra Singh chahar , 12 Years ago
Grade Upto college level
anser 1 Answers
Askiitians Tutor Team

To derive the expression for the potential energy of an electric dipole in a uniform electric field, we first need to understand the relationship between the dipole moment, the electric field, and the forces acting on the dipole. An electric dipole consists of two equal and opposite charges separated by a distance, and its dipole moment \( \mathbf{P} \) is defined as \( \mathbf{P} = q \cdot \mathbf{d} \), where \( q \) is the charge and \( \mathbf{d} \) is the separation vector between the charges.

Understanding the Forces on the Dipole

When an electric dipole is placed in a uniform electric field \( \mathbf{E} \), it experiences a torque that tends to align it with the field. The torque \( \mathbf{\tau} \) acting on the dipole is given by:

  • Torque: \( \mathbf{\tau} = \mathbf{P} \times \mathbf{E} \)

This torque will cause the dipole to rotate until it reaches an equilibrium position where the potential energy is minimized.

Deriving the Potential Energy Expression

The potential energy \( U \) of the dipole in the electric field can be derived from the work done against the torque when the dipole is rotated from a reference position. The work done \( dW \) in rotating the dipole through an angle \( d\theta \) is given by:

  • Work Done: \( dW = \tau \, d\theta = P E \sin(\theta) \, d\theta \)

To find the total work done when the dipole is rotated from an angle \( \theta_0 \) to \( \theta \), we integrate:

  • Potential Energy: \[ U(\theta) = -\int_{\theta_0}^{\theta} P E \sin(\theta') \, d\theta' \]

Assuming the reference position \( \theta_0 = 90^\circ \) (where \( \sin(90^\circ) = 1 \)), the potential energy becomes:

  • Final Expression: \[ U(\theta) = -\mathbf{P} \cdot \mathbf{E} = -PE \cos(\theta) \]

Analyzing Orientation and Potential Energy

The potential energy expression \( U(\theta) = -PE \cos(\theta) \) indicates how the energy varies with the angle \( \theta \) between the dipole moment and the electric field. Let's examine the two extreme cases:

Maximum Potential Energy

The potential energy is maximized when \( \cos(\theta) \) is at its minimum value, which occurs at \( \theta = 180^\circ \). In this orientation, the dipole is aligned opposite to the electric field. The potential energy at this position is:

  • Maximum Energy: \[ U_{\text{max}} = PE \]

Diagrammatically, this can be represented as follows:

  • Dipole moment \( \mathbf{P} \) pointing left (opposite to \( \mathbf{E} \))
  • Electric field \( \mathbf{E} \) pointing right

Minimum Potential Energy

The potential energy is minimized when \( \cos(\theta) \) is at its maximum value, which occurs at \( \theta = 0^\circ \). In this case, the dipole is aligned with the electric field. The potential energy at this position is:

  • Minimum Energy: \[ U_{\text{min}} = -PE \]

In this orientation, the diagram would show:

  • Dipole moment \( \mathbf{P} \) pointing right (aligned with \( \mathbf{E} \))
  • Electric field \( \mathbf{E} \) also pointing right

Summary of Key Points

In summary, the potential energy of an electric dipole in a uniform electric field is given by \( U = -\mathbf{P} \cdot \mathbf{E} \). The energy is maximized when the dipole is anti-aligned with the field and minimized when it is aligned. Understanding these orientations helps in visualizing how dipoles behave in electric fields, which is fundamental in electrostatics and various applications in physics and engineering.

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