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An electron and a proton,each have de broglie wavelength of 1nm(a) find the ratio of their momentum(b) compare the kinetic energy of the proton with that of the electron

Hima yeldo , 9 Years ago
Grade 12
anser 1 Answers
Vikas TU
As U have asked it twice,
Reposting the answer for better ease:
 
Since the de-broglie wavelengths are same their momentum would be same too but would have different velocities as their massess are different.
And Kinetic Energy => P^2/2m
For Proton.
Kp = P^2/2mp
and
For electron,
Ke = P^2/2me
Kp/Ke = me/mp 
where me and mp are the massess of the electron and the proton respectively.
Last Activity: 9 Years ago
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