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This can be solved using an energy method.We can solve this by equating the potential energy of the bow to the kinetic energy of the arrow.The bow can be treated as a type of spring. The potential energy of a spring is:(1/2)kx2, wherekis the stiffness andxis the amount the spring is stretched, or compressed.Therefore, the potential energyPEof the bow is:PE= (1/2)(200)(0.75)2= 56.25 JThe kinetic energy of a particle is:(1/2)mv2, wheremis the mass andvis the velocity.The arrow can be treated as a particle since it is not rotating upon release.Therefore, the kinetic energyKEof the arrow is:KE= (1/2)(0.05)v2If we assume energy is conserved, thenPE=KESolving for the velocity of the arrowvwe getv= 47.4 m/s
sher mohammad
b.tech iit delhi
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