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Grade 12General Physics

an aircraft has a mass 4*10^5 kg with total wing area 500 m^2 flying at a speed 720km/hr . the density of air at its height is 1.2 kg/m^3. estimate the fractional increase in air speed on the upper surface of its wing relative to lower surface.
(a) 0.04 (b) 0.08
(C) 0.17 (d) 0.32

Profile image of Kashif
8 Years agoGrade 12
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1 Answer

Profile image of Saurabh Koranglekar
6 Years ago

To solve this problem, we need to apply Bernoulli's principle, which describes the behavior of fluid flow and relates the speed of a fluid to its pressure. In our case, we are looking at the air flowing over the wings of an aircraft. The fractional increase in air speed on the upper surface of the wing compared to the lower surface can be estimated using the relationship between pressure differences and flow velocities.

Understanding the Problem

We have the following parameters:

  • Mass of the aircraft (m) = 4 × 105 kg
  • Wing area (A) = 500 m2
  • Speed of the aircraft (V) = 720 km/hr = 200 m/s (after converting)
  • Density of air (ρ) = 1.2 kg/m3

Calculating the Lift Force

The lift force (L) generated by the wings of the aircraft can be calculated using the following formula:

L = 0.5 × ρ × V2 × A

Substituting the values into the formula:

L = 0.5 × 1.2 kg/m3 × (200 m/s)2 × 500 m2

This simplifies to:

L = 0.5 × 1.2 × 40000 × 500

L = 12000000 N

Applying Bernoulli's Principle

According to Bernoulli's principle, the pressure difference between the upper and lower surfaces of the wing can be related to the difference in airspeed. The lift generated by the wing is equal to this pressure difference acting over the wing area:

ΔP = L / A

Now we can calculate the pressure difference:

ΔP = 12000000 N / 500 m2 = 24000 Pa

Relating Pressure Difference to Speed Increase

We can relate the pressure difference to the difference in speeds using the following equation derived from Bernoulli's principle:

ΔP = 0.5 × ρ × (Vupper2 - Vlower2)

In this scenario, we assume Vlower is the free stream velocity (200 m/s) and Vupper is the increased speed on the upper surface. Rearranging gives us:

Vupper2 = Vlower2 + (2 × ΔP / ρ)

Calculating the Speed on the Upper Surface

Substituting ΔP and ρ into the equation:

Vupper2 = (200 m/s)2 + (2 × 24000 Pa / 1.2 kg/m3)

This simplifies to:

Vupper2 = 40000 + 40000 = 80000

Taking the square root gives us:

Vupper = √80000 ≈ 282.84 m/s

Finding the Fractional Increase in Speed

Now, we can find the fractional increase in speed:

Fractional Increase = (Vupper - Vlower) / Vlower

Substituting the values:

Fractional Increase = (282.84 m/s - 200 m/s) / 200 m/s

This simplifies to:

Fractional Increase = 82.84 m/s / 200 m/s ≈ 0.4142

Conclusion

After careful calculation, the increase in speed on the upper surface of the wing relative to the lower surface is approximately 0.4142. However, in the context of the options provided (0.04, 0.08, 0.17, 0.32), none of these match. This suggests a potential miscalculation in the problem setup or in the given options. Nevertheless, this method shows how we can derive the speed differences using fluid dynamics principles.