Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        all is thrown horizontally with a speed Vo. angle of actual velocity with horizontal, just before hitting the ground is 60o​. find the height from which the ball was thrown.`
2 years ago

## Answers : (1)

Vikas TU
9762 Points
```							Horizontal and Vertical components of the final velocity are=>V’cos60 = V0 (after balancing)orV’= 2V0In y direcn. the comonent is: => V'sin60 => V0root(3)Applying newton's eqns. of motion in y – direcn. we get,V0root(3) = 0 + gtandh = 0  + 0.5gt^^2substituting the t value in the above eqn. we get,h = 3V0^2/2g m.
```
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions