all is thrown horizontally with a speed Vo. angle of actual velocity with horizontal, just before hitting the ground is 60 o . find the height from which the ball was thrown.

Question

all is thrown horizontally with a speed Vo. angle of actual velocity with horizontal, just before hitting the ground is 60 o ​. find the height from which the ball was thrown.

Vikas TU · Answer

Horizontal and Vertical components of the final velocity are=> V’cos60 = V0 (after balancing) or V’= 2V0 In y direcn. the comonent is: => V'sin60 => V0root(3) Applying newton's eqns. of motion in y – direcn. we get, V0root(3) = 0 + gt and h = 0 + 0.5gt^^2 substituting the t value in the above eqn. we get, h = 3V0^2/2g m.

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all is thrown horizontally with a speed Vo. angle of actual velocity with horizontal, just before hitting the ground is 60 o . find the height from which the ball was thrown.

all is thrown horizontally with a speed Vo. angle of actual velocity with horizontal, just before hitting the ground is 60^o. find the height from which the ball was thrown.

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all is thrown horizontally with a speed Vo. angle of actual velocity with horizontal, just before hitting the ground is 60 o ​. find the height from which the ball was thrown.

all is thrown horizontally with a speed Vo. angle of actual velocity with horizontal, just before hitting the ground is 60o​. find the height from which the ball was thrown.

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all is thrown horizontally with a speed Vo. angle of actual velocity with horizontal, just before hitting the ground is 60 o . find the height from which the ball was thrown.

all is thrown horizontally with a speed Vo. angle of actual velocity with horizontal, just before hitting the ground is 60^o. find the height from which the ball was thrown.