Grade 11VectorsAbcde is a regular hexagon .prove rhat ab+ac+ad+ae+af=6ao Shriya mishra 7 Years agoGrade 11
Deepak Kumar Shringi7 Years agoAB+AC+AD+AE+AF=(AB+AE)+(AC+AF)+AD=AD+AD+AD+=3AD=3(2AO)=6AOtherefore,AB+AC+AD+AE+AF=3(2AD)=6AO.