Question icon
Grade 11Vectors

Abcde is a regular hexagon .prove rhat ab+ac+ad+ae+af=6ao

Profile image of Shriya mishra
7 Years agoGrade 11
Answers icon

1 Answer

Profile image of Deepak Kumar Shringi
7 Years ago

AB+AC+AD+AE+AF
=(AB+AE)+(AC+AF)+AD
=AD+AD+AD+=3AD=3(2AO)=6AO
therefore,AB+AC+AD+AE+AF=3(2AD)=6AO.