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`        A wooden cube is found to float in water with 1/2cm of of its vertical side  above the water.on keeping a weight of 50gm over its top, it is just  submerged in the  water  find the specific gravity`
2 years ago

Utsav Basu
70 Points
```							Let the side of the cube be a cmThus the volume of above water surface = (a2/2)cm3So, a volume of  (a2/2)cm3 of the cube is sufficient to displace 50gm i.e. 50cm3 of water to support the 50gm place upon it.Thus, (a2/2)cm3 = 5cm3or,      a = 10cm Therefore, after placing the weight of 50gm,Buoyant force = 1000gWeight = (m + 50)g But, Buoyant force = WeightSo, 1000g = (m + 50)gor,  m = 950 Thus, density of cube = 950gm/1000cm3 = 0.95gm/cm3Therefore, specific gravity = 0.95gm/cm3
```
2 years ago
HABEEB UR RAHMAN
15 Points
```							  Let the side of the cube be s cmThus the volume of above water surface = (s2/2)cm3So, a volume of  (s2/2)cm3 of the cube is sufficient to displace 50gm i.e. 50cm3 of water to support the 50gm place upon it.Thus, (s2/2)cm3 = 5cm3or,      s= 10cm Therefore, after placing the weight of 50gm,Buoyant force = 1000gWeight = (m + 50)g But, Buoyant force = WeightSo, 1000g = (m + 50)gor,  m = 950 Thus, density of cube = 950gm/1000cm3 = 0.95gm/cm3Therefore, specific gravity = 0.95gm/cm3
```
3 months ago
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• Mind Map
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