A wooden cube is found to float in water with 1/2cm of of its vertical side above the water.on keeping a weight of 50gm over its top, it is just submerged in the water find the specific gravity

Question

Utsav Basu · Answer

Let the side of the cube be a cm Thus the volume of above water surface = (a 2 /2)cm 3 So, a volume of (a 2 /2)cm 3 of the cube is sufficient to displace 50gm i.e. 50cm 3 of water to support the 50gm place upon it. Thus, (a 2 /2)cm 3 = 5cm 3 or, a = 10cm Therefore, after placing the weight of 50gm, Buoyant force = 1000g Weight = (m + 50)g But, Buoyant force = Weight So, 1000g = (m + 50)g or, m = 950 Thus, density of cube = 950gm/1000cm 3 = 0.95gm/cm 3 Therefore, specific gravity = 0.95gm/cm 3

HABEEB UR RAHMAN · Answer

Let the side of the cube be s cm Thus the volume of above water surface = (s 2 /2)cm 3 So, a volume of (s 2 /2)cm 3 of the cube is sufficient to displace 50gm i.e. 50cm 3 of water to support the 50gm place upon it. Thus, (s 2 /2)cm 3 = 5cm 3 or, s= 10cm Therefore, after placing the weight of 50gm, Buoyant force = 1000g Weight = (m + 50)g But, Buoyant force = Weight So, 1000g = (m + 50)g or, m = 950 Thus, density of cube = 950gm/1000cm 3 = 0.95gm/cm 3 Therefore, specific gravity = 0.95gm/cm 3

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A wooden cube is found to float in water with 1/2cm of of its vertical side above the water.on keeping a weight of 50gm over its top, it is just submerged in the water find the specific gravity

A wooden cube is found to float in water with 1/2cm of of its vertical side above the water.on keeping a weight of 50gm over its top, it is just submerged in the water find the specific gravity

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A wooden cube is found to float in water with 1/2cm of of its vertical side above the water.on keeping a weight of 50gm over its top, it is just submerged in the water find the specific gravity

A wooden cube is found to float in water with 1/2cm of of its vertical side above the water.on keeping a weight of 50gm over its top, it is just submerged in the water find the specific gravity

2 Answers

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