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A uniform elastic string has length a1 when tension is T1 and length a2 when tension is T2 . The amount of work done in streching it from its natural length to (a1+a2) is ?
When Tension is T1=> the elongation let x1.then l + x1 =a1 and T1 = kx1 = k(a1 – l) When Tension is T2=> the elongation let x2.then l + x2 = a2 and T2 = kx2 = k(a2 – l)Work done,dW = – k(x1 + x2)dx => -k(a1 + a2 – 2l)dxIntegerating both sides, from (a1 + a2) to l. we get,W = -k[3a1l – a2l – a1^2 – a2^2 -2a1a2 – 2l^2] J.
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