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A train accelerates from 36 km/h to 54 km/h in 10 sec. (i) Acceleration (ii) The distance traveled by car.

A train accelerates from 36 km/h to 54 km/h in 10 sec.
(i) Acceleration
(ii) The distance traveled by car.

Grade:9

2 Answers

Harshit Singh
askIITians Faculty 5963 Points
3 years ago
699-344_Screenshot 2021-04-07 at 11.26.14 PM.png

Thanks
Meemansha Sharma
13 Points
2 years ago
U=36km/h  = 36×1000/3600 =10
V=54km/h   =54×1000/3600 =15
T=10sec
A= v-u/t
   =15-10/10
   = 0.5m/s
 
D=S=ut+1/2×at²
       =10×10+1/2×0.5×10×10
       =100+25
       =125m
 

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