×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
A super bowl is to bounce elastically back and forth between two rigid walls at a distance D from each other neglecting gravity and assuming the velocity of Super Bowl to be we not horizontally the average force being exerted by the superbowl on each wall is
A super bowl is to bounce elastically back and forth between two rigid walls at a distance D from each other neglecting gravity and assuming the velocity of Super Bowl to be we not horizontally the average force being exerted by the superbowl on each wall is

```
3 years ago

Sanjana
11 Points
```							As the ball do back and forth motion,the distance covered by the ball is 2dSo time taken=2d/v∆p=2mvAs F∆t=∆pF=2mv/2d/vAs v go upper side and become v^2and 2 from both upper and lower side get cancelled out and we get-F=mv^2/d
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions