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A super bowl is to bounce elastically back and forth between two rigid walls at a distance D from each other neglecting gravity and assuming the velocity of Super Bowl to be we not horizontally the average force being exerted by the superbowl on each wall is
As the ball do back and forth motion,the distance covered by the ball is 2dSo time taken=2d/v∆p=2mvAs F∆t=∆pF=2mv/2d/vAs v go upper side and become v^2and 2 from both upper and lower side get cancelled out and we get-F=mv^2/d
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