a stone released from a height h reaches the ground in time T. when will be at 1/6h below the point of release
mahesh , 7 Years ago
Grade 11
1 Answers
Aashu Mittal
Last Activity: 7 Years ago
Since, S=ut-1/2gt^2Therefore,-h=-1/2gT^2------(1) [u=0]Suppose that stone will reach h/6 at time t. Then,-h/6=-1/2gt^2h=3gt^2------------(2)Putting value of h from (1) in (2)Then, 1/2gT^2=3gt^2 t^2=1/6T^2 Taking square root both sides t=1/√6T Answer