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Grade: 11
        
A stone is thrown with velocity 15m/s horizontally. Determine the tangential and normal acceleration of the stone 1 second after it begins to move.
one year ago

Answers : (1)

Arun
24494 Points
							
 
In x direcn.,
Vx = 15cos(thetha)
In y direcn.,
Vy = 15sin(thetha) – g*1
 
acclern. in x dircn. = > (Vx – 15costhetha)/1 = 0
accln. in y dircn. = > Vy – 15sinthetha)/1 = > -g
Hence net acclen.is in downward direcn that is => g m/s^2
 
 
Regards
Arun (askIITians forum expert)
one year ago
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